((x^2-3)/(9-x))=0

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Solution for ((x^2-3)/(9-x))=0 equation: 


D( x )

9-x = 0

9-x = 0

9-x = 0

9-x = 0 // - 9

-x = -9 // * -1

x = 9

x in (-oo:9) U (9:+oo)

(x^2-3)/(9-x) = 0

1*x^2 = 3 // : 1

x^2 = 3

x^2 = 3 // ^ 1/2

abs(x) = 3^(1/2)

x = 3^(1/2) or x = -3^(1/2)

x in { 3^(1/2), -3^(1/2) }

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